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Wewaii [24]
4 years ago
5

HELP PLEASE ASAP!!!!!!

Mathematics
1 answer:
lesya692 [45]4 years ago
6 0
Alright, as we can see the large rectangle's area is 4x² + 9x + 2.

You can also see that gray rectangle's area inside the larger rectangle is
x² + 4x + 3.

So if we want to find the white area in-between the two rectangles we will need to SUBTRACT the two formulas! (Subtract the large rectangle from the smaller one)

To do so we will need to subtract the like terms.
The like terms are 4x² and x², 9x and 4x, 2 and 3!

So first we do 4x² - x² and you get 3x²
Next, we do 9x - 4x and you get 5x
Lastly, we do 2 - 3 and you get -1

Now we put our solutions together and you get...

3x² + 5x - 1

This is the are for the white region of your problem. :D  glad to help
 

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Step by step workout of ;<br> log x^3+log 5x=5 log 2-log 2/5
Charra [1.4K]

Answer:

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Step-by-step explanation:

log  \: {x}^{3}  + log \: 5x = 5log \: 2 - log \:  \frac{2}{5}  \\  \\  \therefore \: log( {x}^{3}  \times 5x) = log  {2}^{5} - log \:  \frac{2}{5}  \\  \\ \therefore \: log( 5{x}^{4}) = log 32 - log \:  \frac{2}{5} \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(32  \times  \frac{5}{2}  \bigg) \\  \\ \therefore \: log( 5{x}^{4}) = log  \bigg(16  \times  5) \\  \\ \therefore \: 5{x}^{4}=  16  \times  5 \\  \\ \therefore \: {x}^{4}=   {2}^{4}   \\  \\  \huge \purple{ \boxed{\therefore \: {x} = 2}}

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hope this helps
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