Becky is collecting money for a fundraiser. She wants to collect more than $1,663.00 and has already raised $299.00. Becky avera
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The instantaneous velocity of the 15 kg. mass just after collision can be found by the principle of linear momentum.
a) The speed of the 15 kg. just after collision is <u>2 m/s</u>.
b) The type of collision is <u>inelastic collision</u>
c) The compression of the spring is approximately <u>0.323 m</u>.
Reasons:
The given parameters are;
Mass of the block attached to the spring, m₁ = 15.0 kg
Force constant of the spring, K = 575 N/m
Mass of the stone that strikes the block, m₂ = 3.00 kg
Speed of the stone, v₂ = 8.00 m/s
Speed with which the stone rebounds, v₃ = 2.00 m/s
a) The total initial momentum = 3 kg. × 8 m/s = 24 kg·m/s
The final momentum, just after collision = 3 × (-2) kg·m/s + 15 kg ×v₁
By conservation of momentum, we have;
24 kg·m/s = 3 × (-2) kg·m/s + 15 kg ×v₁
The speed of the 15 kg. just after collision, v₁ = <u>2 m/s</u>.
b) A collision is elastic when the kinetic energy of the collision is conserved
The initial kinetic energy, K.E.₁ = 0.5 × 3 kg. ×(8 m/s)² = 96 J
The sum of the final kinetic energy are;
0.5 × 3 kg. × (2 m/s)² + 0.5 × 15 kg × (2 m/s)² = 36 J
The initial kinetic energy ≠ The final kinetic energy
Therefore, <u>the collision is not elastic</u>
(c) The kinetic energy given by the block = The elastic potential energy gained by the spring
Kinetic energy of the block, K.E. = 0.5 × 15 kg × (2 m/s)² = 30 J
Elastic energy gained by the block = 0.5 × K × x² = 0.5 × 575 N/m × x²
Therefore;
0.5 × 575 N/m × x² = 30 J
The compression of the spring, <em>x</em> ≈ <u>0.323 m</u>.
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<em>Questions;</em>
<em>(a) The speed of the 15 kg mass immediately after the collision</em>.
<em>(b) Determine the type of collision; Elastic or inelastic collision</em>.
<em>(c) The distance to which the spring is compressed by the block</em>.
This problem is providing us with the reaction whereby methane is produced from solid carbon and gaseous hydrogen, as well as its Kp and asks for the total pressure at equilibrium for a specified addition of reactants. At the end, the answer turns out to be 11.7 atm.
<h3>Chemical equilibrium</h3>In chemistry, when a chemical reaction takes place, it proceeds until a point called equilibrium, where the concentration of all the species start becoming unchanged. Thus, we can use equilibrium expressions whenever we needed pressures or concentrations at equilibrium.
In this case, for the reaction we were given, we can write the following equilibrium expression, where the solid carbon is excluded:
Which can also be written in terms of the reaction extent and the initial pressure of hydrogen:
Thus, we calculate the initial pressure of hydrogen with the temperature and volume of the flask:
Hence, we solve for x in the equilibrium expression as follows:
Where the correct value is 6.64 atm because the 12.6 atm turns out into a negative pressure for hydrogen at equilibrium. Finally, we calculate the total pressure with:
Learn more about chemical equilibrium: brainly.com/question/13444482