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nikdorinn [45]
4 years ago
7

How do I solve this?

Mathematics
1 answer:
Alecsey [184]4 years ago
3 0
You have to find LCD (lowest common denominator) in this case it will be 5x:

\frac{u}{x}+\frac{5u}{x}- \frac{u}{5x}=\frac{5*u}{5x}+\frac{5*5u}{5*x}- \frac{u}{5x}=\frac{5u+25u-u}{5x}=\frac{29u}{5x}

Answer: C
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There are 32 green and purple markers in a box. The ratio of green markers to purple markers is 3:5. How many of the markers are
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3:5

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A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

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