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Dimas [21]
3 years ago
11

A toy rocket is launched straight up from the top of a building. The function that models the height as a function of time is h(

t)=-16^2+200t+50. At what height was the rocket launched?
Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

Answer: 50 ft

Step-by-step explanation:

The correct function is h(t)=-16t^2+200t+50.

Hi, to answer this question we simply have to replace t =0 in the function given:

h(t)=-16t^2+200t+50.

h (0) = -16t^2+200t+50.

h(0) = 50

When the time is 0, the rocket is at the top of the building.

The rocket was launched from a 50 ft height.

Feel free to ask for more if needed or if you did not understand something.  

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Find the sum of 5x-y and (2xy+xy)
devlian [24]
Since neither 5x nor -y has a "like term" in <span>2xy+xy, the sum of these quantities is simply    

</span><span>2xy+xy + 5x - y = 3xy + 5x - y

You might want to write this as  y(3x -1) + 5x. </span>
8 0
3 years ago
Three times a number increased by 20, is 14 less than the product of five and the 1095
Zinaida [17]

3x + 20 = (5 \times 1095) - 14 \\ 3x + 20 = 5475 - 14 \\ 3x = 5461 - 20 \\ 3x = 5441 \\ x =  \frac{5441}{3}

8 0
2 years ago
(05.07 MC)
Pavlova-9 [17]

Answer:

  0.65 square inch

Step-by-step explanation:

Each triangle has an area given by ...

  A = 1/2bh = 1/2·(0.5 in)(0.4 in) = 0.10 in²

The square base has an area given by ...

  A = s² = (0.5 in)² = 0.25 in²

The total area is that of the square base and 4 triangles:

  S = 0.25 in² + 4×0.10 in² = 0.65 in²

6 0
4 years ago
Read 2 more answers
Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?
aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

 two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

  consecutive terms is d, then

  U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

 the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0
3 years ago
The largest doll is 12 inches tall. The height of each of the other dolls is 710 the height of the next larger doll. Write an ex
Ahat [919]
Largest doll = 12 inches
2nd doll = (12) x 0.7
3rd doll = (12 x 0.7) x 0.7
4th doll = [(12 x 0.7) x 0.7) x 0.7

So, the height of the nth doll can be expressed as: 12 x 0.7^(n-1)

Example: 4th doll = 12 x 0.7^(4-1) = 12 x 0.7^3
6 0
3 years ago
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