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Dimas [21]
3 years ago
11

A toy rocket is launched straight up from the top of a building. The function that models the height as a function of time is h(

t)=-16^2+200t+50. At what height was the rocket launched?
Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

Answer: 50 ft

Step-by-step explanation:

The correct function is h(t)=-16t^2+200t+50.

Hi, to answer this question we simply have to replace t =0 in the function given:

h(t)=-16t^2+200t+50.

h (0) = -16t^2+200t+50.

h(0) = 50

When the time is 0, the rocket is at the top of the building.

The rocket was launched from a 50 ft height.

Feel free to ask for more if needed or if you did not understand something.  

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insens350 [35]

Answer:

12.02 inches

Step-by-step explanation:

recall, volume of a cylinder is given by

V = πr²h

where r is the radius of the cylinder and h = the height

hence

9080 = π x r² x 20

r² = 9080 ÷ 20π = 144.513

r = √144.513 = 12.02 inches

7 0
3 years ago
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emmainna [20.7K]

Answer:

A. Add the endpoints

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Step-by-step explanation:

To find the midpoint of the vertical line segment with endpoints (0, 0) and (0, -12).

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Step 2: Divide -12 by 2

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Therefore, the y-coordinate of the midpoint of a vertical line segment is -6.

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5 0
3 years ago
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dybincka [34]
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