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zheka24 [161]
3 years ago
9

Jason and Yolanda both drew a simple random sample from a non-normally distributed population of 25,000. Jason’s sample consiste

d of 0.24% of the population, while Yolanda’s sample consisted of 0.32% of the population. Whose sample can be used to make inferences about the population?
neither Jason’s sample nor Yolanda’s sample
only Jason’s sample
only Yolanda’s sample
both Jason’s sample and Yolanda’s sample
Mathematics
2 answers:
Andreas93 [3]3 years ago
6 0
Based on the given options, the most likely answer to this question is "both Jason’s sample and Yolanda’s sample". Moreover, we can see that the population is large. Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
UkoKoshka [18]3 years ago
3 0

Answer:  Last Option is correct.

Step-by-step explanation:

Since we have given that

Total number of population = 25000

Percent of sample of Jason = 0.24%

Percent of sample of Yolanda's = 0.32%

So, Number of population according to Jason's sample is given by

\frac{0.24}{100}\times 25000\\\\=0.0024\times 25000\\\\=60

Number of population according to Yolanda's sample is given by

\frac{0.32}{100}\times 25000\\\\=0.0032\times 25000\\\\=80

Both the sample can be used to make inferences about the population

Hence, Last Option is correct.

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Even more trig ratios see attachment
egoroff_w [7]

Step-by-step explanation:

1. Use the Pythagorean theorem to solve for side KM:

  • 16^2+KM^2=34^2
  • 256+KM^2=1156
  • KM^2=900
  • KM=30

2. Cosine is adjacent over hypotenuse, so cosine of M would be KM/34, or 30/34

3. Tangent is opposite over adjacent, so tangent of L will be KM/16, or 30/16

4. Sine is opposite over hypotenuse, so sine of M will be 16/34

5. KM=30, solved for in step 1.

hope this helps!!

4 0
2 years ago
Please solve the following question.
mylen [45]

Answer:

103, 776

Step-by-step explanation:

There are 48 possibilities, and you are picking 3.

Now, the order does matter (aka, if the same 3 athletes won but got different places, we would still consider it to be a separate possibility)

(this is considered "without repetitions")

the number of permutations (arrangement combinations where the order does matter) without repetitions formula:

Number of permutations

without <em>repetitions </em>= nPr

= \frac{n!}{(n-r)!}

(

[the P is for combinations [where the order does matter, if the order didn't matter then it would be C, and it would be a different formula.]

n is the total number of objects.

r is the number of objects selected]

<em>(a repetition would be like two versions of the same person competing, which doesn't make sense)</em>

{the ! means factorial:

5! = 5 x 4 x 3 x 2 x 1}

{for example, if there are 5 people to give a presentation, and they can go in any order [but cannot repeat their presentation], so they all must fill 5 slots}

{for the first slot there are 5 choices, the second slot there are 4 choices...}

)

So, if we follow this formula:

\frac{n!}{(n-r)!}

n: 48

r: 3

\frac{48!}{(48-3)!}

= \frac{48!}{45!}

=\frac{48 * 47*46*45!}{45!}

(the 45! cancel out)

= 48 * 47 * 46

= 103, 776

(or, without the formula:

for the first choice (lets say of gold), there are 48 options

for the second choice (lets say silver), there are 47 options left to choose from

for the third choice (lets say bronze), there are 46 options left to choose from

)

3 0
2 years ago
7-5x+1 please answer i need this NOW!!!!!!!!!!!!!!!!!!!!!
Alisiya [41]

Answer:x=8/5 or 1.6

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Step-by-step explanation:

5 0
3 years ago
Need help asap (giving brainliest)
Nikolay [14]

Answer:

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2 years ago
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fomenos

You sleep 1/3 of the day.

5 0
2 years ago
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