Question

On a coordinate plane, rhombus A B C D is shown. Point A is at (1, 1), point B is at (negative 2, negative 3), point C is at (negative 5, 1), and point D is at (negative 2, 5). What is the perimeter of rhombus ABCD? 10 units 20 units units units

Answer 1

Answer:

20 units

Step-by-step explanation:

We are given that

On a coordinate plane , rhombus ABCD in which point A is at (1,1) and point B is at (-2,-3), point C is at (-5,1) and D is at (-2,5).

We have to find the perimeter of rhombus ABCD.

Distance formula : $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula

Side AB=$\sqrt{(-2-1)^2+(-3-1)^2}=5 units$

We know that sides of rhombus are equal

Therefore, AB=BC=CD=AD=5 units

Perimeter of rhombus=$4\times side$

Perimeter of rhombus=$4\times 5=20 units$

Answer: 20 units

Answer 2

Answer:

20 units

Step-by-step explanation: