Answer:
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
Step-by-step explanation:
Parallel lines have same slopes.
Line 1, L1: 5x-2y=20 is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.
5x-2y = 20
-2y = -5x+20
y = (-5/-2)x+20/(-2)
y = (5/2)x-10 hence m1=5/2 and y-intercept is -10
Line 2 , L2: y-y1 = m (x-x1), m=m2=m1=5/2
Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
Answer:
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Step-by-step explanation:
Well 15 is over 8 so figure out how many times 8 goes into 15 then the rest of 15 replaces it over the 8
Absolute Extrema<span>. If a function has an </span>absolute<span> maximum at x = b , then f (b) is the largest value that f can attain. Similarly, if a function has an </span>absolute<span> minimum at x = b , then f (b) is the smallest value that f can attain.
</span>The strategy for tracking the sign of the derivative is useful for more than determining where a function is increasing or decreasing. It is also useful for locating the relative extrema of a function. At a relative extrema<span>, a function changes from increasing to decreasing or decreasing to increasing.
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