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3 years ago

An airplanes altitude changed -415 feet over 5 minutes.what was the mean change of altitude in feet per minute

Mathematics

1 answer:

Zinaida [17]3 years ago

8 0

83 ft per minute an that is how I got my awnser

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Determine whether the graph is the graph of a function.

photoshop1234 [79]

Answer:

Yes

Step-by-step explanation:

Unless the line is vertical, the graph of any straight line is the graph of a function.

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A vertical line does not map x to one single y-value, so it does not represent a function. Any other line does map each x to a single y-value, so does represent a function.

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What is the greatest common factor of the terms 14c2d and 42c3d ?

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14c^2d
42c^3d

The greatest common factor of the terms 14c^2d and 42c^3d is 14c^2d~

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6(7x-9)+15 simplify equation

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Answer:

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Step-by-step explanation:

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3 years ago

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Dana reflects point A(2,5) across line small script letter lℓ to get image point Upper A primeA′(6,1). What is an equation for

valentinak56 [21]

Firstly, we will draw diagram of the scenario

Dana reflects point A(2,5) across line small script letter lℓ to get image point Upper A primeA′(6,1)

It means that AA' is perpendicular bisects of line(l)

so, let's assume it intersects at point M

so, M will be mid-point between A and A'

$M=(\frac{2+6}{2},\frac{5+1}{2})$

$M=(4,3)$

M is a point on line (l)

now, we will find slope of line on AA'

x1=2 , y1=5

x2=6 , y2=1

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{1-5}{6-2}$

$m=-1$

now, we know that line (l) and AA' are perpendicular to each other

so, slope of line(l) is -1/m

slope=1

so, we have slope and a point

$m=1$

$M=(4,3)$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

now, we can plug values

$y-3=1(x-4)$

$y=x-1$

so, the equation of line (l) is

$y=x-7$ ..............Answer

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3 years ago

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The relative locations of a swing set, a garden, and a sandbox in Gina's backyard are shown in the diagram.

Archy [21]

Let us suppose the distance between the sandbox and garden is x feet.

Apply the sine law in the given triangle, we have

$\frac{x}{\sin 65^{\circ}}=\frac{36}{\sin 104^{\circ}}\\
\\
\text{On coss multiplying, we get}\\
x\sin 104^{\circ}=36\sin 65^{\circ}\\
\\
x=\frac{36\sin 65^{\circ}}{\sin 104^{\circ}}\\
\\
x\approx 33.6$

Therefore, in the nearest foot, the distance between the sandbox and garden is 34 foot.

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4 years ago

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