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3 years ago

(-2/3)(5/4) Enter as a fraction, in simplest form

Mathematics

1 answer:

Leviafan [203]3 years ago

5 0

$- \frac{2}{3} \times \frac{5}{4} = - \frac{10}{12} = \frac{ - 5}{6}$

in it's lowest term...

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Which equation is not a linear function:<br> y=2x<br> y=x+2<br> y=x-2<br> y=x²

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Answer:

Step-by-step explanation:

A linear equation can be written in the form

y = mx+b.

y = x² is not linear.

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3 years ago

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Firlakuza [10]

Answer:

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3 years ago

WILL MARK BRAINLIEST. Which of the following statements about the polynomial function given is true?

Katyanochek1 [597]

Answer:

Step-by-step explanation:

because as X approaches infinity, the negative sign will cause it to go opposite of X.

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3 years ago

Read 2 more answers

Which points are the approximate locations of the foci of the ellipse? Round to the nearest tenth. (−2.2, 4) and (8.2, 4) (−0.8,

Studentka2010 [4]

The graph is attached.

Answer:

(-2.2, 4) and (8.2, 4)

Step-by-step explanation:

In an ellipse, there is a minor radius and a major radius.

Let major radius be = a

Let minor radius be= b

From the graph, we are given:

Major radius, a = 6

Minor radius, b = 3

Now, let's find the distance from the center to the focus using the formula:

$\sqrt{a^2 - b^2}$

Substituting values, we have:

$= \sqrt{6^2 - 3^2}$

$= \sqrt{36 - 9}$

$= \sqrt{27} = 5.916$

≈ 5.2

We can see from the graph that center coordinate is (3, 4). Therefore, the approximate locations of the foci of the ellipse would be:

(3-5.2, 4) and (3+5.2, 4)

= (-2.2, 4) and (8.2, 4)

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3 years ago

X^2=4x-15 solve with Quadratic formula

bulgar [2K]

Answer:

$x=2+i\sqrt{11}$

$x=2-i\sqrt{11}$

Step-by-step explanation:

we have

$x^{2} =4x-15$ -------> $x^{2}-4x+15=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-4x+15=0$

$a=1\\b=-4\\c=15$

substitute in the formula

$x=\frac{-(-4)(+/-)\sqrt{-4^{2}-4(1)(15)}} {2(1)}$

$x=\frac{4(+/-)\sqrt{16-60}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{4(+/-)\sqrt{-44}} {2}$

$x=\frac{4(+/-)2i\sqrt{11}} {2}$

$x=\frac{4(+)2i\sqrt{11}}{2}=2+i\sqrt{11}$

$x=\frac{4(-)2i\sqrt{11}}{2}=2-i\sqrt{11}$

7 0

4 years ago