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MaRussiya [10]
3 years ago
7

(-2/3)(5/4) Enter as a fraction, in simplest form

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

-  \frac{2}{3}  \times  \frac{5}{4}  =  -  \frac{10}{12}  =  \frac{ - 5}{6}

in it's lowest term...

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What is tan 11 pie/6
tia_tia [17]

Answer:

5.75

Step-by-step explanation:

5 0
3 years ago
Which linear function represents the line given by the point slope equation y - 2 - 4(x - 3)? O RX) - 6x 1 O Rx) = ax - 6 O P(x)
Sever21 [200]

Answer:

Use the given functions to set up and simplify O R X . y − 2 − 4 ( x − 3 ) = − 4 x + y + 10 O R X = − 4 x + y + 10

Step-by-step explanation:

4 0
3 years ago
Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!! I don't understand it!
katrin2010 [14]

Answer:

  13.98 in²

Step-by-step explanation:

I don't understand it, either.

Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.

__

The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.

The area of a segment is given by the formula ...

  A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.

Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...

  A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²

Rounded to hundredths, this is ...

  ≈ 13.98 in²

3 0
3 years ago
What is (2+y)³ written out?
Aleksandr-060686 [28]
{ \left( 2+y \right)  }^{ 3 }\\ \\ =\left( 2+y \right) \left( 2+y \right) \left( 2+y \right) \\ \\ =\left( 2+y \right) \left( 4+4y+{ y }^{ 2 } \right)

\\ \\ =2\left( 4+4y+{ y }^{ 2 } \right) +y\left( 4+4y+{ y }^{ 2 } \right) \\ \\ =8+8y+2{ y }^{ 2 }+4y+4{ y }^{ 2 }+{ y }^{ 3 }\\ \\ ={ y }^{ 3 }+6{ y }^{ 2 }+12y+8
5 0
3 years ago
How do you put f(8)=-1,f(6)=0 into point slop form?​
Mademuasel [1]

Answer:

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute [SF]:                    m=\frac{0+1}{6-8}
  2. Add/Subtract:                      m=\frac{1}{-2}
  3. Simplify:                               m=\frac{-1}{2}

<u>Step 3: Write Function</u>

<em>Substitute into general form.</em>

  • Point 1: y + 1 = -1/2(x - 8)
  • Point 2: y = -1/2(x - 6)
4 0
3 years ago
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