The SAT provides students with all of the following except:

Identify what part of speech the underlined word in the sentence is:

Elza [17]

Answer:

Which one is the underlined word?

Explanation:

I couldn't see the underlined word. Please rewrite the question in order for me to help you. (Tip: use Ctrl+U to write an underlined word.)

5 0

3 years ago

LO explain two challenges that the organization has experience

Delicious77 [7]

Lack of direction is one of the most common organizational problems and it stems from two root causes: The leader or leaders rarely discuss or chart a deliberate direction or strategy for the future, or they fail to communicate a coherent message about the strategy to all members of the organization. Hopefully this helped.

5 0

3 years ago

Once you have your heap structure created, next you must use it as a backing structure to a priority queue. Develop a PriorityQu

saveliy_v [14]

Using the knowledge in computational language in python it is possible to write a code that Develop a PriorityQueue data structure in a file.

<h3>Writting the code in python:</h3>

import sys

class Node:

def __init__(self,key):

self.left = None

self.right = None

self.val = key

self.parent = None

class MinHeap:

def __init__(self, maxsize):

self.maxsize = maxsize

self.size = 0

self.Heap = Node(-1 * sys.maxsize )

self.FRONT = self.Heap

# A utility function to do inorder tree traversal

def isLeaf(self, node):

if node.left == None and node.right == Node:

return True

return False

# Function to swap two nodes of the heap

def swap(self, node1, node2):

node1.data, node2.data = node2.data, node1.data

# Function to heapify the node at pos

def minHeapify(self, node):

# If the node is a non-leaf node and greater

# than any of its child

if not self.isLeaf(node):

if (node.data > node.left.data or

node.data > node.right.data):

# Swap with the left child and heapify

# the left child

if node.left.data < node.right.data:

self.swap(node, node.left)

self.minHeapify(node.left)

# Swap with the right child and heapify

# the right child

else:

self.swap(node, node.right)

self.minHeapify(node.right)

# Function to insert a node into the heap

def insert(self, element):

if self.size >= self.maxsize :

return

self.size+= 1

self.bst_insert(FRONT, element)

current = FRONT

while current.parent != None and current.data < current.parent.data:

self.swap(current, current.parent)

current = current.parent

# Function to print the contents of the heap

def Print(self):

self.inorder()

# Function to build the min heap using

# the minHeapify function

def inorder(self, root):

if root:

inorder(root.left)

print(root.val)

inorder(root.right)

def bst_insert(self, root, node):

if root is None:

root = node

else:

root.next = node

self.FRONT = node

# Driver Code

if __name__ == "__main__":

r = Node(50)

bst_insert(r,Node(30))

bst_insert(r,Node(20))

bst_insert(r,Node(40))

bst_insert(r,Node(70))

bst_insert(r,Node(60))

bst_insert(r,Node(80))

# Print inoder traversal of the BST

inorder(r)

print('The minHeap is ')

minHeap = MinHeap(15)

minHeap.insert(5)

minHeap.insert(3)

minHeap.insert(17)

minHeap.insert(10)

minHeap.insert(84)

minHeap.insert(19)

minHeap.insert(6)

minHeap.insert(22)

minHeap.insert(9)

minHeap.minHeap()

minHeap.Print()

print("The Min val is " + str(minHeap.remove()))

See more about python at brainly.com/question/13437928

#SPJ1

6 0

1 year ago

- A box contains only blue and black glass

Tomtit [17]

Answer:

D.

Explanation:

Blue beads are 3 times more likely to be pulled. Therefore, since there are 12 beads in total the ratio which would fit the ratio of probability to pull blue beads compared to black beads would be 9/12 leaving 3/12 probability to pull a black bead. if you simplify the fractions you get 3/4 and 1/4 where 1/4 (the probability to pull a black bead) is three times less than the probability to pull a blue bead.

3 0

3 years ago

Paint should be stored and mixed in an OSHA-approved room with all of the following, EXCEPT: A) Adequate ventilation B) Ventilat

damaskus [11]

Answer:

C) Unshielded electrical devices

Explanation:

5 0

3 years ago

Read 2 more answers