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omeli [17]
3 years ago
11

What are the answers for a-c... Need the answers asap...thank you

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0
For Letter C You Need to Count The Squares in the Pond And the Half Squares are a Half. The Answer for C is 33 Because The Half and the Other Half is a Whole So I Made 3 New Wholes and Added it to the 30.
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Consider the sequence: 12, 17, 22, ... , ... , .... What is the 405th term of this sequence?
Mice21 [21]
A_n= a₁+(n-1)d

a₁ first term

n terms

d distance between each value

a_n= 12+(405-1)(5)=2032
7 0
3 years ago
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Laura family is going on vaction.they will drive 4,180 miles over the next two weeks.about how many miles will they drive on ave
RSB [31]
If she can drive 4180 miles in <em>two </em>weeks, it would make sense that she would drive an average of <em>half </em>that distance in <em>one </em>week. Half of 4180 is 2090, so she averaged 2090 miles each week.
6 0
3 years ago
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Which answer describes the transformation of f(x)=x2−1 to g(x)=(x−1)2−1 ?
artcher [175]
A vertical translation 1 unit down since for example x is 1, if u plug it in both equations it is f(1)=1*2-1 which equals f(1)=1 and the point is (1,1) for the other one, g(1)=(1-1)2-1 it equals g(1)=-1
4 0
3 years ago
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What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
how much money has to be invested at 3.3% interest compounded constinuously to have $45,00 after 19 years
Sedaia [141]
P=$24038.60 has to be invested to have $45000 after 19 years
3 0
3 years ago
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