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True [87]
4 years ago
7

The population for Gulch Dry has been declining according to the function P(t)= 8000. 2^-t/29 where t is the number of years sin

ce 1910
a) what was the town's population in 1990
b) in what year will the town's population first fall under 125 people?
Mathematics
1 answer:
Iteru [2.4K]4 years ago
6 0
A)

\bf 1990-1910=80\leftarrow t
\\\\\\
P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}}
\\\\\\
P(80)=8000\cdot \cfrac{1}{2^{\frac{80}{29}}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^{80}}}

and surely you know how much  that is.

b)

\bf P(t)=125\\\\\\  125=8000(2)^{-\frac{t}{29}}\implies \cfrac{125}{8000}=2^{-\frac{t}{29}}\implies \cfrac{1}{64}=2^{-\frac{t}{29}}
\\\\\\
\textit{now we take log to both sides}
\\\\\\
log\left( \frac{1}{64} \right)=log\left( 2^{-\frac{t}{29}} \right)\implies log\left( \frac{1}{64} \right)=-\frac{t}{29}log\left( 2 \right)
\\\\\\
log\left( \cfrac{1}{64} \right)=-\cfrac{tlog(2)}{29}\implies \cfrac{-29log\left( \frac{1}{64} \right)}{log(2)}=t\implies 174=t

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
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