Answer:
12
Step-by-step explanation:
Use the relation between 3 is to 51
eventually... you will
Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
Answer:
(-6,1)
Step-by-step explanation:
A. Reflection
When you reflect a point (x, y) across the x-axis, the x-coordinate remains the same, but the y-coordinate gets the opposite sign.
Thus, D (-3,-1) ⟶ D' (-3, 1)
B. Translation
When you translate a point horizontally, its x-coordinate changes, but the y-coordinate. remains unchanged.
You translated the point 3 units to the left.
D'(-3, 1) ⟶ D"(-6,1)
4 (e)
sin^8 x - cos^8 x
= (sin^4 x + cos^4 x)(sin^4 x - cos^4 x)
= (sin^4 x + cos^4 x)(sin^2 x - cos^2x)(sin^2 x +cos^2 x)
= (sin^4x + cos^4 x)( sin^2 x- cos^2 x)
Sorry I cant do 4 (d).
Answer:
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
Step-by-step explanation:
Because it is a equilateral triangle, it means all sides have the same length.
AB = AC
5/4 y - 1 = 7/3 y - 2
5/4 y - 7/3 y = -2 +1
-13/12 y = -1
y = 12/13
input y to the equation.
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
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