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3 years ago

I need help with this proof

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

See explanation

Step-by-step explanation:

Consider two triangles ABF and EDF. These triangles are two right triangles, because angles B and D are right anges.

In these triangles,

∠ABF ≅ ∠EDF - as two right angles;
BF ≅ FE - given;
∠AFB ≅ ∠EFD - as vertical angles when two lines AD and BE itersect.

By ASA postulate (or HA postulate) these triangles are congruent, so

ΔABF ≅ ΔEDF

Congruent triangles have congruent corresponding parts, so

FA ≅ EF

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Answer:

a) P(X =16 ) = 0.1853

b) $P(X \leq 12)$ = 0.0684

Step-by-step explanation:

GIVEN DATA:

n = 16

p = 0.90

from relation given probabllity can be solve

$P(X) = ^nC_x * p^x * ( 1 - p)^{n-x}$

$P(X =16 ) = ^{16}C_{16} * 0.90^x * ( 1 - 0.90)^{16-16}$

P(X =16 ) = 0.1853

b) $P(X \leq 12) = 1 - P(X \geq 13)$

= 1 - [ P(X = 13) +P(X = 14) +P(X = 15) +P(X = 16) ]

$= 1 - [ ^{16}C_{13} * 0.90^{13} * (1 - 0.90)^3 +^{16}C_{14} * 0.90^{14} * (1 - 0.90)^2 +^{16}C_{15} * 0.90^{15} * (1 - 0.90)^1 +^{16}C_{16} * 0.90^{16} * (1 - 0.90)^0 ]$

= 0.0684

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3 years ago

The quotient of 6 times a number and 16

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6x=16
÷6 both sides
x=16/6 or 8/3

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May I have brainliest please? :)

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