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3 years ago

Can someone help me please ?

Mathematics

1 answer:

sladkih [1.3K]3 years ago

3 0

I would go for C because if i rounded most of the decimals it would end up as that

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David’s statement shows a previous balance of $5834.53, a payment of $150, and new transactions totaling $325. His APR is 20.4%.

DaniilM [7]

Finance charge
(5,834.53−150)×(0.204÷12)=96.64

New balance
5,834.53−150+96.64+325
=6,106.17

8 0

3 years ago

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the bookstall Inc is a specialty book store concentrating on used books sold via the internet.Paperbacks are $1.55 each and hard

podryga [215]

Answer:

$2.65

Step-by-step explanation:

to get a weighted mean

divide the total revenue by the number of books

Revenue

(1.55 * 40) + (4.85 * 20)

$159

weighted mean

159/60

$2.65

3 0

3 years ago

Q13<br> Please help me solve this….

KonstantinChe [14]

Answer:

Choice C

$\frac{\sqrt{186}+\sqrt{15}}{18}$

Step-by-step explanation:

The quadrant in which an angle lies determines the signs of the trigonometric functions sin, cos and tan

If an angle Θ lies in quadrant IV, cos(Θ) is positive and both sin(Θ) and tan(Θ) are negative

Two of the trigonometric identities we can use are

1. $\sin^2(\theta) + cos^2(\theta) = 1$ and

2. $\cos(A-B) = \cos A\cos B - \sin A\sin B$

Using identity 1, we can solve for cos(s) and cos(t)

$sin(s)=-\frac{\sqrt{3}}{3}, sin^{2}(s)=\frac{3}{9}=\frac{1}{3}\\cos^{2}(s)=1-sin^{2}(s)=1-\frac{1}{3}=\frac{2}{3}; cos(s)=\pm\sqrt{\frac{2}{3}}\\\\$

$sin(t)=-\frac{\sqrt{5}}{6}, sin^{2}(t)=\frac{5}{36}cos^{2}(t)=1-sin^{2}(t)=1-\frac{5}{36}=\frac{31}{36};cos(t)=\pm\frac{\sqrt{31}}{6}$

Since both angles lie in quadrant IV, both cos(s) and cos(t) must be positive so we only consider the positive signs of both values

Using identity 2, we can solve for cos(s-t)

$cos(s-t)=cos(s)cos(t)+sin(s)sin(t)=\frac{\sqrt{2}}{\sqrt{3}}.\frac{\sqrt{31}}{6}+(-\frac{\sqrt{3}}{3})(-\frac{\sqrt{5}}{6})$

Multiplying numerator and denominator of the first term by $\sqrt{3}$ gives us the final expression as

$\frac{\sqrt{3}}{\sqrt{3}}\frac{\sqrt{2}}{\sqrt{3}}.\frac{\sqrt{31}}{6}+(-\frac{\sqrt{3}}{3})(-\frac{\sqrt{5}}{6})=\frac{\sqrt{186}}{18}+\frac{\sqrt{15}}{18}= \frac{\sqrt{186}+\sqrt{15}}{18}$

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2 years ago

The solution of an equation with two variables x and y, is

katen-ka-za [31]

Answer:

Thats not a question

Step-by-step explanation:

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3 years ago

The moon is about 240,000 miles from earth what is the distance written as a whole number multiplied by the power of 10

algol [13]

24 times 10 with the exponent as 4

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3 years ago

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