As we know the formula to calculate the line of equation is y - y1 = m (x - x1)
Where m is the slope. y1 is the first y co ordinate. x1 is the first x co ordinate.
Now we do know that the slope of parallel line is the same as the slope of the original line.
So parallel line slope is 3 so slope for our line is 3. Hence equation is y - 7 = 3 (x - 2) which becomes y = 3x + 1.
Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
Answer:
The answer is
Step-by-step explanation:
The line of g(x) is steeper and has a lower y-intercept
:)
That’s the answer <3
Answer:
7 1/6
Step-by-step explanation:
