write the equation in slope intercept form of the line that has a slope of 2 and contains the point (1,1)
1 answer:
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Answer:
Step-by-step explanation:
When answering a problem like this, you first isolate the absolute value. TO do this, first subtract 8 from both sides, to get –2|4–5y|=-4. Then divide both sides of the equation to get |4–5y|=2. The next thing you do is split the equation into 4-5y=2 and 4-5y=-2, because the contents of the absolute value could be negative or positive, and simplifying both into y = 2/5, and y = 6/5y.
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Answer:
see the attached graph
Step-by-step explanation:
When an equation is in <em>standard form</em> (or almost standard form), I like to put it into <em>intercept form</em> for graphing. Here, it is convenient to divide the equation by 2 to put it in standard form (coefficients mutually prime).
x +3y = -3
Now, it is convenient to divide by the constant on the right (-3) to put the equation into intercept form:
x/(-3) +y/(-1) = 1
The denominators are the x- and y-intercepts, respectively. Plot those, (-3, 0) and (0, -1), and draw the line through them.
