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UkoKoshka [18]
3 years ago
9

Need help SOON please. I'll be forever grateful. see attached image!

Mathematics
1 answer:
vichka [17]3 years ago
8 0
Ok i cant answer the exact answer cause i don’t have paper put i’ll give you the format
it’s is
y2-y1
———-
x2-x1

that’s is the formula, you take the second y coordinate and subtract it from the first y then you do the second x coordinate and subtract it from the first x coordinate. hope this helps you
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HELP WILL MARK BRAINLIEST!!!
Alenkasestr [34]

Answer:

y = 12

Step-by-step explanation:

set up equation for 'y varies inversely with x':  y = k/x

where 'k' is the constant of variation

8 = k/6

therefore, k = 48

value of y when x = 4:  y = 48/4; therefore, y = 12

                     

7 0
3 years ago
Identify, graph, and state the symmetries for the polar equation r=2+2sintheta.
IRINA_888 [86]

Answer:

Graph = Cardioid

Axis of symmetry = y-axis

Critical points= \frac{\pi}{2} , \frac{3\pi }{2}

Step-by-step explanation:

General equation for this type of cardioid is:

a ± b sinθ

Condition for a cardioid = \frac{a}{b} = 1

Axis of symmerty according to the graph of 2 + 2 sinθ is along y-axis.

Critical points:

r = 2 + 2 sinθ  ⇒ r = 2(1 + sinθ) ⇒ r' = 2 cosθ  

 ∵derivative of 1 + sinθ = cosθ

For finding critical point the derivative is equal to zero,

2 cosθ = 0    ⇒    cosθ = 0

the value of cosθ is equal to zero at intervals: \frac{\pi}{2} , \frac{3\pi }{2}

So, critical points = \frac{\pi}{2} , \frac{3\pi }{2}

3 0
3 years ago
What's the possibility of choosing a spade in a deck of 52 cards?
Mashcka [7]
There are 4 suits in a deck of cards: hearts, diamonds, spades, and clubs.
Therefore there are 13 cards of each suit (52/4).
The possibility of choosing a spade in a deck of 52 cards is 13/52 = 25%
6 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5
DanielleElmas [232]

Answer:

1

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that csc(x)=1/sin(x) and sec(x)=1/cos(x).

Thus:

\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}

=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }

Let's do the first part first: (Recall how to divide fractions)

\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}

For the second term:

\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}

So, all together: (same denominator; combine terms)

\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}

Note the numerator; it can be derived from the Pythagorean Identity:

sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)

Thus, we can substitute the numerator:

\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1

Everything simplifies to 1.

7 0
3 years ago
Pls help me!!!!!!!!!!!!!!!
Volgvan
The answer is A because you have to subtract the pink ribbon by the red ribbon.
3 0
3 years ago
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