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3 years ago

How does sin 30degrees compare to sin -30degrees?

Mathematics

1 answer:

KiRa [710]3 years ago

7 0

The sine function is an odd function, so the sine of -30° is the opposite of the sine of 30°.

sin(30°) = 1/2

sin(-30°) = -1/2

The sine of 30° is greater than the sine of -30°.

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The sycamore grove contains 30 sycamo

Zinaida [17]

Answer:

40 trees

Step-by-step explanation:

Let the total number of trees be x.

75% of all the sycamore trees in the park are 30 trees.

So,75%of x=30

or,(75/100)*x=30

or,x=(30*100)/75

or,x=40 [ANS]

7 0

3 years ago

Round to the nearest ten for 2,420

kotykmax [81]

I'm pretty sure it's just 2,420.

5 0

3 years ago

Read 2 more answers

I need help please!!!!?

Lena [83]

The answer is:

the 3rd quadrant ! (Quadrant III)

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3 years ago

PLEASE HELP! urgent! Write the equation of a line in a slope-intercept form and standard form

m_a_m_a [10]

Answer:

$y = \frac{3}{4}x -3$ --- Slope intercept

$4y - 3x =- 12$ --- Standard form

Step-by-step explanation:

Given

The attached linear graph

Required

The equation

Select any two points on the line

$(x_1,y_1) = (0,-3)$

$(x_2,y_2) = (4,0)$

Next, calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

So, we have:

$m = \frac{0 --3}{4 - 0}$

$m = \frac{3}{4}$

The slope intercept is then calculated using:

$y = m(x - x_1) + y_1$

So, we have:

$y = \frac{3}{4}(x - 0) -3$

$y = \frac{3}{4}(x) -3$

$y = \frac{3}{4}x -3$

Multiply through bu 4

$4y = 3x - 12$

Subtract 3x from both sides

$4y - 3x =- 12$ --- Standard form

7 0

3 years ago

Describe a sequence of transformations that exhibits the similarity between the pair of figures shown.

kow [346]

Answer:

Reflection across the x-axis followed by dilation by a scale factor of $\frac{1}{4}$ with the center of dilation at the origin

Step-by-step explanation:

Rectangle EFGD has vertices at points E(-6,8), F(0,8), G(0,1) and D(-6,1).

1 transformation - reflection across the x-axis with the rule

$(x,y)\rightarrow (x,-y)$

So, the image rectangle E''F''G''D'' has vertices with coordinates

$E(-6,8)\rightarrow E''(-6,-8);$
$F(0,8)\rightarrow F''(0,-8);$
$G(0,1)\rightarrow G''(0,-1);$
$D(-6,1)\rightarrow D''(-6,-1).$

2 transformation - dilation by a scale factor of $\frac{1}{4}$ with the center of dilation at the origin. This transformation has the rule

$(x,y)\rightarrow (\frac{1}{4}x,\frac{1}{4}y)$

Thus,

$E''(-6,-8)\rightarrow E'(-\frac{3}{2},-2);$
$F''(0,-8)\rightarrow F'(0,-2);$
$G''(0,-1)\rightarrow G'(0,-\frac{1}{4});$
$D''(-6,-1)\rightarrow D'(-\frac{3}{2},-\frac{1}{4}).$

These are exactly vertices of rectangle E'F'G'D'.

7 0

3 years ago