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3 years ago

If each side of the square is 7 7 units long, how long is the diagonal to the nearest tenth

Mathematics

1 answer:

SOVA2 [1]3 years ago

4 0

I’m not quite sure if you are saying each side is 7 or 77 so I did both.

If the side length is 7, then 9.9 is the answer.

If the side length is 77, then 108.9 is the answer.

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2. √2x-5-√x+6=0(solving the following radical equations and check for extraneous solutions)

Norma-Jean [14]

I assume the equation is

√(2x - 5) - √(x + 6) = 0

Note the domains for the root expressions:

• √(2x - 5) : 2x - 5 ≥ 0 ⇒ x ≥ 5/2

• √(x + 6) : x + 6 ≥ 0 ⇒ x ≥ -6

So any valid solution we find must be at least 5/2.

Move one term to the other side.

√(2x - 5) = √(x + 6)

Take squares.

(√(2x - 5))² = (√(x + 6))²

2x - 5 = x + 6

Solve for x :

x = 11

5 0

1 year ago

Can someone please help me for A, B, and C

galben [10]

bat sakin mo inaasa dapat ikaw ang mag answer Nyan

salamat nalang sa pt

7 0

2 years ago

Find the number of 3-digit numbers formed using the digits 1 to 9, without repetition, such the numbers either have all digits l

Tasya [4]

Answer: 120

Step-by-step explanation:

The total number of digits from 1 to 9 = 10

The number of digits from less than 5 (0,1,2,3,4)=5

Since repetition is not allowed so we use Permutations , then the number of 3-digit different codes will be formed :-

$^5P_3=\dfrac{5!}{(5-3)!}=\dfrac{5\times4\times3\times2!}{2!}=5\times4\times3=60$

The number of digits from greater than 4 (5,6,7,8,9)=5

Similarly, Number of 3-digit different codes will be formed :-

$^5P_3=60$

Hence, the required number of 3-digit different codes = 60+60=120

3 0

3 years ago

Simplify: 2√3/16 - √75/16 + 2√27/16 a. 3/4√3 b. 1/2√3 c.5/4√3 d.0

erastova [34]

Answer:

Step-by-step explanation:

2√3/16 - √75/16 + 2√27/16

2/4√3 - 5/4√3 + 6/4√3

3/4√3

5 0

2 years ago

-4+ =-1 what is the missing number?

Oksi-84 [34.3K]

T h e. a n s w e r I s t h r e e

4 0

3 years ago