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3 years ago

20 POINTS PLS HELP

Mathematics

1 answer:

harkovskaia [24]3 years ago

5 0

Answer: 50 holes

Step-by-step explanation: I find an easy way to answer questions like this is by 'dimensional analysis'....

Dimensions mins/holes and mins

mins / (mins/holes) = holes (because 'mins' cancel out)

25 mins / (6 mins/12 holes) = 300/6 holes = 50 holes

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Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By (5.3) and (4.1) C The equ

frosja888 [35]

Answer:

$2x-y=7$

Step-by-step explanation:

Here we are given two coordinates through which our lines passes through. Now we are going to use the two point form to find the equation of the line.

The two point form is given as

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$

Here we are given two coordinates . Thus replacing them in the formula and simplifying it will give us the equation of the line.

$\frac{y-1}{x-4}=\frac{3-1}{5-4}$

$\frac{y-1}{x-4}=\frac{2}{1}$

$(y-1)=2(x-4)$

$y-1=2x-8$

subtracting y and adding 8 on both sides we get

$2x-y=7$

Hence this is our equation of the line passing through (5,3) & (4,1)

7 0

3 years ago

Ms. Adler bought x bags of

OLga [1]

Answer:

Step-by-step explanation:

Number of bags = Total money spent / Cost of each bag

x = number of bags of chips

Simply divide 17.50 by 1.25 to work out how many bags of chips he can purchase.

Number of bags = Total money spent / Cost of each bag

$x = \frac{17.50}{1.25}$ = ?

8 0

4 years ago

Read 2 more answers

Marley borrows $500 to pay for a new computer she will pay back the loan in full in 30 days after she receives her paycheck this

gulaghasi [49]

Answer:

single payment of a loan

Step-by-step explanation:

4 0

3 years ago

NEED HELP ASAP

KengaRu [80]

Answer:

Part 1) Triangle GHI, JKL

Part 2) $(40*15)and(8*3)$ , $(18*6)and(4.5*1.5)$

Step-by-step explanation:

we know that

If two figures are similar

then

the ratio of their corresponding sides are equal and is called the scale factor

Part 1)

case a) triangle GHI

If ABC and GHI are similar

then

$\frac{4}{24}=\frac{3}{7}=\frac{5}{25}$

but

$0.17 \neq 0.43 \neq \ 0.20$

therefore

Triangle GHI is not similar to triangle ABC

case b) triangle DEF

If ABC and DEF are similar

then

$\frac{4}{44}=\frac{3}{33}=\frac{5}{55}$

$0.09=0.09=0.09$

therefore

Triangle DEF is similar to triangle ABC

case c) triangle MNO

If ABC and MNO are similar

then

$\frac{4}{10}=\frac{3}{7.5}=\frac{5}{12.5}$

$0.4=0.4=0.4$

therefore

Triangle MNO is similar to triangle ABC

case d) triangle JKL

If ABC and JKL are similar

then

$\frac{4}{21}=\frac{3}{20}=\frac{5}{29}$

$0.19 \neq 0.15 \neq 0.17$

therefore

Triangle JKL is not similar to triangle ABC

Part 2)

case a) If the rectangles are similar, then

$\frac{40}{8}=\frac{15}{3}$

$5=5$

therefore

the rectangles are similar

case b) If the rectangles are similar, then

$\frac{18}{4.5}=\frac{6}{1.5}$

$4=4$

therefore

the rectangles are similar

case c) If the rectangles are similar, then

$\frac{1,225}{3.5}=\frac{144}{1.2}$

$350\neq120$

therefore

the rectangles are not similar

case d) If the rectangles are similar, then

$\frac{13}{5.2}=\frac{5}{2.5}$

$2.5\neq 2$

therefore

the rectangles are not similar

3 0

4 years ago

A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process,

Anastasy [175]

Step-by-step explanation:

A manufacturer of computer memory chips produces chips in lots of 1000. If nothing has gone wrong in the manufacturing process, at most 7 chips each lot would be defective, but if something does go wrong, there could be far more defective chips. If something goes wrong with a given lot, they discard the entire lot. It would be prohibitively expensive to test every chip in every lot, so they want to make the decision of whether or not to discard a given lot on the basis of the number of defective chips in a simple random sample. They decide they can afford to test 100 chips from each lot. You are hired as their statistician.

There is a tradeoff between the cost of eroneously discarding a good lot, and the cost of warranty claims if a bad lot is sold. The next few problems refer to this scenario.

Problem 8. (Continues previous problem.) A type I error occurs if (Q12)

Problem 9. (Continues previous problem.) A type II error occurs if (Q13)

Problem 10. (Continues previous problem.) Under the null hypothesis, the number of defective chips in a simple random sample of size 100 has a (Q14) distribution, with parameters (Q15)

Problem 11. (Continues previous problem.) To have a chance of at most 2% of discarding a lot given that the lot is good, the test should reject if the number of defectives in the sample of size 100 is greater than or equal to (Q16)

Problem 12. (Continues previous problem.) In that case, the chance of rejecting the lot if it really has 50 defective chips is (Q17)

Problem 13. (Continues previous problem.) In the long run, the fraction of lots with 7 defectives that will get discarded erroneously by this test is (Q18)

Problem 14. (Continues previous problem.) The smallest number of defectives in the lot for which this test has at least a 98% chance of correctly detecting that the lot was bad is (Q19)

(Continues previous problem.) Suppose that whether or not a lot is good is random, that the long-run fraction of lots that are good is 95%, and that whether each lot is good is independent of whether any other lot or lots are good. Assume that the sample drawn from a lot is independent of whether the lot is good or bad. To simplify the problem even more, assume that good lots contain exactly 7 defective chips, and that bad lots contain exactly 50 defective chips.

Problem 15. (Continues previous problem.) The number of lots the manufacturer has to produce to get one good lot that is not rejected by the test has a (Q20) distribution, with parameters (Q21)

Problem 16. (Continues previous problem.) The expected number of lots the manufacturer must make to get one good lot that is not rejected by the test is (Q22)

Problem 17. (Continues previous problem.) With this test and this mix of good and bad lots, among the lots that pass the test, the long-run fraction of lots that are actually bad is (Q23)

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3 years ago