So to graph you problem you should first consider that the one side of the bar is 150feet because it is in the other partitioned of the fence and the function of it would be 150(x) because the barn's area is calculated through it length time width. I hope this will help
I think the answer is: a score of <span>38 on a test for which = 27 and s = 10</span>
-12 + 9 - (-3) - 11
Remember PEMDAS: This is the order of operation.
P-Paragrahp
E-Exponent
M-Multiply
D-Divide
A-Add
S-Subtract
1st step: PEM
-(-3) is actually -1 * -3 = + 3
-12 + 9 + 3 - 11
2nd step: D is not possible, so we do A.
9 + 3 = 12
3rd Step: Subtract
12 - 12 - 11 = 0 - 11 = -11 CHOICE B.
A Trapezoid needs to have one pair of sides parallel.
Two of the points already plotted have the same Y value ( 3)
So the 4th dot, should have the same Y value as the first dot, which is 1.
The 4th dot should be plotted at C (5,1)
Answer:
The height of the building is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC
we have
substitute and solve for BC
Find the height of the building
The height of the building (h) is equal to
