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pishuonlain [190]
3 years ago
11

angle and angle b are complentary angles. if angle a = (2x-5) and m angle b = (5x+4) then find the measure of angle a

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0

complementary angles = 90

2x-5 + 5x+4 = 90

combine like terms

7x-1 =90

7x = 91

divide by 7

x =13

angle a

2x-5

2*13-5

26-5

21

Angle a: 21

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Answer:

The equation of the line that is parallel to  is  and the equation of the line that is perpendicular to  is .

Let be a line whose equation is:

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Whose explicit form is:

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Where:

- Independent variable.

- Dependent variable.

The slope and x-intercept of the line are  and , respectively.

There are two facts:

A line is parallel to other line when the former has the same slope of the latter.

A line is perpendicular to other line when the former has a slope described the following form (), where  is the slope of the former.

Then, the equation of the line that is parallel to  is  and the equation of the line that is perpendicular to  is .

To learn more on lines, we kindly invite to check this verified question: brainly.com/question/2696693

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2 years ago
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What is the slant height ?
LekaFEV [45]

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A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

\implies 12w^3 - 12=0

w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
How does the graph of y = sqr x + 2 compare to the graph of the parent square root function?
posledela
Is the 2 in the sqr? If not, the graph just moves up by 2 units
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