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user100 [1]
3 years ago
8

A. Positive B. Negative C zero D. Unidentified

Mathematics
2 answers:
Yuki888 [10]3 years ago
7 0
The slope is A) Positive 
SashulF [63]3 years ago
7 0
Your answer is a. positive
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2 years ago
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vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

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2 years ago
If DE≅EF, CD = v + 45, and CF = 4v, what is the value of v?
irinina [24]

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<h2><u>since </u><u>DE≅EF</u></h2>

<u>CD=</u><u>CF </u><u>(</u><u>cpct)</u>

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<h2><u>hope</u><u> it</u><u> helps</u><u> you</u><u><</u><u>3</u></h2>
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2 years ago
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