Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between and minutes. Find the probability that a randomly selected passenger has a waiting time minutes. 0 7 greater than 1.25

Answer 1

Complete Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between   0  and   7  minutes. Find the probability that a randomly selected passenger has a waiting time  greater than 1.25  minutes.

Answer:

The probability is  $P(X > 1.25) = 0.8214$    

Step-by-step explanation:

From the question we are told that

    The start time is  a  = 0 minutes

     The end time is  b =  7 minutes

Generally the probability that a randomly selected passenger has a waiting time  greater than 1.25  minutes is mathematically represented as

      $P(X > 1.25) = 1 - P(X \le 1.25)$  

=>    $P(X > 1.25) = 1 - \frac{1.25 - a}{ b- a }$  

=>    $P(X > 1.25) = 1 -0.1786$

=>   $P(X > 1.25) = 0.8214$