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Rama09 [41]
3 years ago
6

Pls help me with math

Mathematics
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

Like terms are those terms whose variables and powers are same. For question no. 1

  • 4p, 2p, p
  • m^2 , 3m^2
  • 5ac, 7ca
  • 5v , 9v and 2wv , vw
  • 6pq, 2qp, 3pq
  • 3d, 2d
  • 4mn, 2nm
  • 4x^2y , x^2y
  • 5ba, ab

Now for question no. 2

The like terms from the given term is C. 3ab, 2ba

If u have any confusion then u can ask hope it will help you

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7 0
3 years ago
Can I get help solving?
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Answer:

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7 0
3 years ago
(6x1000)+(1x10)+(8x1/1)+(9x1/10)+(4/100)=
Vera_Pavlovna [14]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's evaluate ~

\qquad \tt \dashrightarrow \:(6 \times 1000) + (1 \times 10) + (8 \times  \frac{1}{1} ) + (9 \times  \frac{1}{10} ) +  \frac{4}{100}

\qquad \tt \dashrightarrow \:6000 + 10 + 8  + \frac{9}{10}  +  \frac{4}{100}

\qquad \tt \dashrightarrow \: \dfrac{600000 + 1000 + 800 + 90 + 4}{100}

\qquad \tt \dashrightarrow \: \dfrac{601894}{100}

or

\qquad \tt \dashrightarrow \:{6018.94}{}

6 0
3 years ago
A app.edulastic.com
timama [110]
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