Question

The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 60. Jake scored 520 on the test. What percent of students scored below Jake? Include a step by step description of the process you used to find that percentage.

Answer 1

Answer:

z score is 0.33

( 0.6293) is the answer the next slot)

and 62.93% is last

Step-by-step explanation:

Answer 2

Subtract the mean from Jake's score:

520 - 500 = 20

Divide by the standard deviation:

20/60 = 0.33

Jake scored 0.33 standard deviation above the mean.

From the Z-table, 0.33 = 0.6293 = 62.93% of students scored below Jake.

Round to 63%