Please help me someone!

Mathematics

2 answers:

ASHA 777 [7]3 years ago

8 0

I think the answer's B! Please don't quote me on this, but I'm almost positive! (:
i hope all is well, and you pass!

lozanna [386]3 years ago

4 0

The answer is C because there is 16 cups in a gallon.

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For problems 12 - 14, Determine whether each sequence appears to be an

marshall27 [118]

Step-by-step explanation:

⇒12)It is an arithmetic sequence.

d=2-1=3-2=4-3=1

a(n) = a +(n-1)d

a(n) = 1+(n-1)1

The next three terms:

a(6) = 1+(6-1)1=6

a(7) = 1+(7-1)1=7

a(8) = 1+(8-1)1=8

⇒13)It is an arithmetic sequence.

d=0-3=-3-0=-6+3=-3

a(n) = a +(n-1)d

a(n) = 3+(n-1)-3

The next three terms:

a(5) = 3+(5-1)-3=-9

a(6) = 3+(6-1)-3=-12

a(7) = 3+(7-1)-3=-15

⇒14)It is <u>not </u>an arithmetic sequence.

⇒15) a(50) = 10 +(50-1)5

=<u>255</u>

<u>I hope this helps</u>

<u />

8 0

3 years ago

(60 points)

natka813 [3]

Answer:

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

$6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}$