Answer:
Step-by-step explanation:
Since G(0) = g(0) = 20, the parabolic graphs of these functions share a y-intercept: (0, 20).
Completing the square puts these equations into vertex form, which simplifies comparisons of the graphs:
G(x) = 2x^2 - 12x + 20 becomes
2(x^2 - 6x + 9 - 9) + 20, or
2(x - 3)^2 - 18 + 20, or 2(x - 3)^2 + 2. Comparing this result to
a(x - h)^2 + k, we see that the vertex is located at (3, 2).
Going through the same process for g(x) 2x^2+12x+20, we get:
g(x) = 2(x + 3)^2 + 2, whose vertex is at (-3, 2).
Next time, please include ALL info pertaining to your question, including the set of possible answer choices. Thank you.
There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.
Even means the graph is symmetric about the y-axis
The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)
because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).
Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
Answer:
314
Step-by-step explanation:
Area is pie(r^2
10x10=100
100x3.14 is 314
