Question

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Answer 1

Area of the figure = 112 in²

Solution:

The given figure is splitted into two shapes.

One shape is square.

Each side of square are equal.

Side = 10 inch

Area of the square = side × side

                               = 10 × 10

                               = 100

Area of the square = 100 in²

The other shape is triangle.

Base of the triangle = 10 in – 6 in = 4 inch

Height of the triangle = 16 in – 10 in = 6 inch

Area of the triangle = $\frac{1}{2}\times \text{base}\times \text{height }$

                                 $=\frac{1}{2}\times4\times6$

                                 = 12

Area of the triangle = 12 in²

Area of the figure = Area of the square + Area of the triangle

                              = 100 in² + 12 in²

Area of the figure = 112 in²

Therefore, area of the given figure is 112 in².

Answer 2

Answer:

Area of figure = area of square + area of triangle

Area = 10 × 10 + 1/2 × 6 × 4

Area = 100 + 12

Area = 112 in²

I hope it helps you