The only factor that both terms have is d
Answer:
<em>If you are asking if that's correct then yes it is</em>
Step-by-step explanation:
Answer:
the answer is 7,348,000
Step-by-step explanation:
X^2(x+4) x 3x^2(x-1)
(X^3+4x^2) x (3x^3 -3x^2)
3x^6 -3x^5+12x^5 -12x^4
3x^6 +9x^5-12x^4
I think that’s how you do it
Answer:
(3x^2+y^2+2xy)(3x^2+y^2-2xy)
Step-by-step explanation:
9x^4+2x^2y^2+y^4
(3x^2+y^2+2xy)(3x^2+y^2-2xy)
Both terms are perfect squares. So you will factor using the difference of squares formula. a^2-b^2=(a+b)(a-b)
Take what the square is for every term.
9x^4. What squared is 9? 3 and take half of the power or 2. That's how you get the 3x^2
2x^2y^2 is the same way. 2xy and 2xy
y^4 is y but dived he powers by 2 to get y^2.
Take one of each and but in () like I have above.
