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3 years ago

a circle has a diameter of 10cm what is the best proximation of this area use 3.14 to approximate for pi

2 answers:

5 0

The meaning of the area is the measurement of a surface in this case a circle, which can be find by using the formula A=πr^2, where r is equal to the radius of the circle.

On this exercise is given that a circle has a diameter of 10cm and it is asked to find its area, as previous said the only way to find the area of a circle is to use the formula A=πr^2, but on this case the radius is not given. As result you have to divide the measurement of the diameter by two, and the number found represents the radius.

10cm/2= 5cm The radius of the circle is 5cm.

Now that the radius is known you can substitute the values in the formula to find the area of the circle.

A=πr^2
A=(3.14)(5)^2
A=(3.14)(25)
A=78.5 cm^2

The area of the circle is 78.5 square centimeters.

hammer [34]3 years ago

4 0

Hello!

The answer would be $75.8^{cm2}$

Hope this helped!

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Let I (x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"

FrozenT [24]

Answer:

Step-by-step explanation:

L(x) means that Student X has an internet connection

C(x,y) means that students X and Y have chatted over the internet

The domain for variables X and Y comprise all students in your class. We now use quantifiers or algebraic functions to express each of the statements:

(A) Jerry does not have an internet connection

L(x) = 0

Where X represents Jerry

(B) Rachel has not chatted over the internet with Chelsea

C(x,y) = 0

Where X and Y represent Rachel and Chelsea

L(x) + L(y) = 0

Where X and Y represent Jan and Sharon. If they have NEVER chatted over (the question didn't say they have never "with each other", it says they have never chatted at all) the internet, then they've probably never had an internet connection!

(D) No one in the class has chatted with Bob

Let Y represent Bob and X1, X2, ..., Xn represent everyone else in the class.

The value of Y is not significant here (because it is raised to the power of zero and that makes it equal to 1 and when 1 is multiplied by any X value, the X value or student remains the same) but we have to put it, to represent Bob.

The quantifier here is C (X1Y°, X2Y°, X3Y°, ..., XnY°)

5 0

3 years ago

Find the sine of both angle A and angle B.

olchik [2.2K]

Sin = opposite/hyp

Sin A = 10/26 = 5/13

Sin b = 24/26 = 12/13

The answer is option A

Hope this helps

6 0

3 years ago

Read 2 more answers

1. (k+7)² =289 2. (2s-1)² =225 3. (x-4)² =169 please help me answer these :)

professor190 [17]

$(k+7)^2 =289\\
|k+7|=17\\
k+7=17\vee k+7=-17\\
k=10 \vee k=-24$

$(2s-1)^2 =225\\
|2s-1|=15\\
2s-1=15\vee 2s-1=-15\\
2s=16 \vee 2s=-14\\
s=8 \vee s=-7$

$(x-4)^2 =169\\
|x-4|=13\\
x-4=13 \vee x-4=-13\\
x=17 \vee x=-9$

6 0

3 years ago

Read 2 more answers

What is the height of the triangle? 12 units 24 units 36 units 72 units.

konstantin123 [22]

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side. The height of the tringle is 24 units. Hence option 2 is the correct option.

<h3>Given information-</h3>

The triangle for the given problem is shown in the image below.

Form the figure the length of the each side is $16 \sqrt{3}$ units.

As all the sides are equal thus the $\Delta MNO$ is a equilateral triangle in which the height of the divides the triangle into two equal part of the length $8\sqrt{3}$ at point R.

<h3>Height of the triangle-</h3>

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.

Now in the $\Delta MRN$ , the length of the hypotenuse is $16 \sqrt{3}$ units and the length of the base is $8\sqrt{3}$ units. Let h is the height of the triangle thus by the Pythagoras theorem,