Answer:
314 m²
Step-by-step explanation:
the surface area of a sphere (As) is
As = 4×pi×r²
our radius r (half of the diameter) here is 5m.
As = 4×3.14×5² = 4×3.14×25 = 100×3.14 = 314 m²
<span>Angle T = Angle C, let them equal x
So x + x + 140 = 180
2x = 40
x = 20
So Angle T = 20 degrees </span>
Answer:the z score is - 1
Step-by-step explanation:
Assuming a normal distribution for the delivery time of sandwiches by Sammy's Sandwich Shop. We would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = delivery times
u = mean delivery time
s = standard deviation
From the information given,
u = 25 minutes
s = 2 minutes
We want to determine the z-score for the number of sandwiches delivered in less than 23 minutes. It becomes
z = (23 - 25)/2 = - 1
Answer:
Please check the explanation.
Step-by-step explanation:
Part a)
Given that the two parallel lines are crossed by a transversal line.
Given that
m∠2 = 2x + 54 and m∠6 = 6x - 11
Angle ∠2 and ∠6 are corresponding angles.
Corresponding angles are congruent.
Thus,
m∠2 = m∠6
2x + 54 = 6x - 11
flipe the equation
6x - 11 = 2x + 54
subtract 2x from both sides
6x - 2x - 11 = 2x - 2x + 54
4x - 11 = 54
adding 11 to both sides
4x - 11 + 11 = 54 + 11
4x = 65
dvide both sides by 4
4x/4 = 65/4
x = 16.2500 (round to 4 decimal places)
Part b)
We have already determined
x = 16.2500
Given
m∠2 = 2x + 54
substitute x = 16.2500 in the euation
= 2(16.2500) + 54
= 86.5°
As angle ∠2 and angle ∠1 lie on a straight line. Hence, the sum of their angles must be 180°.
i.e.
m∠1 + m∠2 = 180°
substituting m∠2 = 86.5° in the equation
m∠1 + 86.5° = 180°
subtracting 86.5° from both sides
m∠1 + 86.5° - 86.5° = 180° - 86.5°
m∠1 = 93.5°
Therefore, the measure of angle m∠1 is:
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
