Curly hair (C) is dominant over straight hair(c). a heterozygous curly haired woman marries a homozygous straight haired man. wi th respect to hair.
a. write the genotypes of man and woman
man:
woman;
b. what % of the children will have curly hair
2 answers:
The woman's genotype is Cc (she's heterozygous)
The man's genotype is cc (he's homozygous)
If you make a punnet square it'll look like this (I hope it works out)
<u>C </u> <u>c </u>
<u>c </u> <em>Cc cc</em>
<u>c </u> <em>Cc cc</em>
Since curly hair (C) is dominant, any genotype with a capital C will have curly hair. This means 2/4 or 50% of children will have curly hair
Answer:
I Can answer B: I think I'd be 75%
Explanation:
I'm pretty sure you have to make a Punnett square, so:
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Explanation:
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