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Furkat [3]
3 years ago
7

Curly hair (C) is dominant over straight hair(c). a heterozygous curly haired woman marries a homozygous straight haired man. wi

th respect to hair.
a. write the genotypes of man and woman
man:
woman;
b. what % of the children will have curly hair

Biology
2 answers:
omeli [17]3 years ago
6 0

The woman's genotype is Cc (she's heterozygous)

The man's genotype is cc (he's homozygous)

If you make a punnet square it'll look like this (I hope it works out)

    <u>C</u>     <u>c</u>

<u>c</u>  <em>Cc   cc</em>

<u>c</u>  <em>Cc  cc</em>

Since curly hair (C) is dominant, any genotype with a capital C will have curly hair. This means 2/4 or 50% of children will have curly hair

kompoz [17]3 years ago
4 0

Answer:

I Can answer B: I think I'd be 75%

Explanation:

I'm pretty sure you have to make a  Punnett square, so:

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Punnett  square:  

          ch         ch

C       Cch       Cch

ch    chch      chch

 

Explanation:

A heterozygous individual is an individual who has two different gene variants (i.e., alleles) at a particular <em>locus</em>. In this case, individuals having the "agouti coat" trait are heterozygous carrying both 'C' and 'ch' alleles. On the other hand, a homo-zygous individual has the same allele at a given <em>locus</em> (here, the 'chch' genotype associated with the albino phenotype). Therefore, as observed in the Punnett Square above, when a heterozygous parent is crossed with a homo-zygous recessive parent for a single gene, alleles segregate in the gametes of both parents so an expected 1:1 phenotypic ratio will be observed.

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