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lina2011 [118]
3 years ago
11

A chef has less than 25.8 pounds of rice. She takes out 5 pounds to use during the day and stores the rest in containers. Each c

ontainer has 2.5 pounds of rice. Let x represent the number of containers. What is the maximum number of containers the chef will be able to fill with rice? 13 12 8 7
Mathematics
2 answers:
Grace [21]3 years ago
7 0
The answer should be eight. Hope this helps! :)
Amiraneli [1.4K]3 years ago
3 0

The chef has less than 25.8 pounds of rice.

She takes out 5 pounds to use during the day and stores the rest in containers.

Quantity of rice stored = 25.8 - 5 = 20.8 pounds

Each container can store 2.5 pounds of rice.

Let x represent the number of containers.

The number of containers that can be filled = 20.8/2.5 = 8.32

So, the maximum number of containers the chef will be able to fill with rice is 8

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Two families are planning a trip to Disney. The Smith family bought tickets for 2 adults and 3 children for $557. The Jones fami
emmainna [20.7K]

<em>An adult ticket costs $205 and a child ticket costs $49.</em>

<h2>Explanation:</h2>

Hello! Recall you have to write complete questions in order to find exact answers. Here I'll assume the complete question as:

<em>Two families are planning a trip to Disney. The Smith family bought tickets for 2 adults and 3 children for $557. The Jones family bought tickets for 2 adults and 1 child </em><em>for $459</em><em>. How much does and adult and child ticket cost?</em>

To solve this problem, we need to write a system of linear equations in two variables. So, we know some facts:

  • Two families are planning a trip to Disney.
  • The Smith family bought tickets for 2 adults and 3 children for $557.
  • The Jones family bought tickets for 2 adults and 1 child for $459.

Let:

x:Cost \ of \ ticket \ per \ adult \\ \\ y: Cost \ of \ ticket \ per \ child

For the Smith family:

Cost for the 2 adults:

2x

Cost for the 3 children:

3y

Total cost:

2x+3y=557

For the Jones family:

Cost for the 2 adults:

2x

Cost for the 1 child:

y

Total cost:

2x+y=459

So we have the following system of linear equations:

\begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}2x+3y=557\\2x+y=459\end{array}\right.

Subtracting (2) from (1):

\begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}2x+3y=557\\-(2x+y=459)\end{array}\right. \\ \\ \\ \begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}2x+3y=557\\-2x-y=-459\end{array}\right. \\ \\ \\ (2x-2x)+(3y-y)=557-459 \\ \\ 2y=98 \\ \\ y=49 \\ \\ \\ Finding \ x \ from \ (1): \\ \\ 2x+3(49)=557 \\ \\ 2x=557-147 \\ \\ 2x=410 \\ \\ x=205

Finally, <em>an adult ticket costs $205 and a child ticket costs $49.</em>

<em></em>

<h2>Learn more:</h2>

System of linear equations: brainly.com/question/13799715

#LearnWithBrainly

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Since 32/100 is not in lowest terms, we divide both the numerator and the denominator by 4 and we get the equivalent fraction 8/25.

This means that 0.32 can be written as the fraction 8/25 which is in lowest terms.

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