Complete question :
From points A and B, the distance between which is 1020 mi, two trains left simultaneously towards each other. The speed of one train was 10 mph greater than the speed of the other one. In 5 hours the trains had not met yet and were 170 mi apart. Find the speed of the trains.
Answer:
Train A = 80 miles per hour
Train B = 90 miles per hour
Step-by-step explanation:
Given that :
Distance between A and B = 1020
Let the speed of A = x
Speed of B = x + 10
Since they both left simultaneously;
Distance traveled after 5 hours will be :
Distance = speed * time
A = x * 5 = 5x
B = (x + 10) * 5 = 5x + 50
After the distance traveled by each of A and B, they are still 170 miles apart
Hence, distance covered after 5 hours ;
Total miles - miles left
1020 - 170 = 850 miles
Hence,
5x + 5x + 50 = 850
10x = 850 - 50
10x = 800
x = 80
Train A = 80 miles per hour
Train B = 80 + 10 = 90 miles per hour
Answer:
It's 3
Step-by-step explanation:
if you go to desmos graphing calculator it'll help you get the solutions for these if you type it in every number and letter and for exponents type ^ its shift then type 6.
Answer:
so how many units are they away from each other
Step-by-step explanation:1,
1.1-2.0 how many units are they away from each other
u could drag the number from the top to the chart below
good luck!
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Answer:
16
Step-by-step explanation:
if c = 4, then
(c)(c) = 16
if I misinterpreted your equation, please tell me.
