Answer:
Step-by-step explanation:
The problem solver "completed the square." He or she took half of the coefficient of x and squared the result, and then added this square and subtracted this square to/from both sides of the equation.
The infinite numbers is represented by D.
1)Shade 56 of the cubes
2)0.056
This is your answer:
<span>Trapezoid
JKLM is congruent to trapezoid J′K′L′M′ because you can map trapezoid
JKLM to trapezoid J′K′L′M′ by reflecting it across the line y = x and
then translating it 1 unit up, which is a sequence of rigid motions.</span>
1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
