Parallel lines have equal slopes, but different y intercepts. So the answer will be in the form y = 2x+c, where b and c are different numbers. Since b = 5, this means c must be some other number. If c = 5, then we'd have the exact same line.
Let's plug in (x,y) = (-5,12), along with the slope m = 2, and solve for c
y = mx+c
12 = 2(-5)+c
12 = -10+c
12+10 = c
22 = c
c = 22
Since m = 2 and c = 22, we go from y = mx+c to y = 2x+22
The the opp side is given by (hypo)^2 = (adj)^2 + (opp)^2. Here, 13^2 = 5^2 + (opp)^2, so that (opp)^2 = 169 - 25 - 144. Then opp = +12. All of these lengths are in Q I. opp 12 Then sin A = -------- = -------- (answer) hyp 13