To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
B is the right answer for this
Answer:
the probability that no customer will arrive in the next 6 minutes = 0.36788 = 0.368
Step-by-step explanation:
If there are 10 customers per hour, this translates to 1 customer per 6 minutes
So, if there's a mean of 1 customer per 6 minutes, to obtain the probability that no customer will come in a 6 minute interval, this becomes a Poisson distribution problem.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
where λ = mean = 1 customer per 6 minutes
x = 0 customer per 6 minutes
P(X=0) = (e⁻¹)(1⁰)/0! = 0.36788 = 0.368
Answer:
It comes with 13.8 ounces of crackers now.
Step-by-step explanation:
12 + 15% = 13.8
Answer:
7x
Step-by-step explanation:
