Part (i)
<h3>Answer:
x^2 + 5x + 6</h3>
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Work Shown:
(x+3)(x+2)
y(x+2) ..... Let y = x+3
y*x + y*2 ... distribute
x(y) + 2(y)
x(x+3) + 2(x+3) .... plug in y = x+3
x*x + x*3 + 2*x + 2*3 ... distribute
x^2 + 3x + 2x + 6
x^2 + 5x + 6
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Part (ii)
<h3>Answer:
4x^2 - 16x + 7</h3>
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Work Shown:
We could follow the same set of steps as shown back in part (i), but I'll show a different approach. Feel free to use the method I used back in part (i) if the visual approach doesn't make sense.
The diagram below is a visual way to organize all the terms. Many textbooks refer to it as "the box method" which helps multiply out any two algebraic expressions.
Each inner cell is found by multiplying the corresponding outer terms. For instance, in the upper left corner we have 2x*2x = 4x^2. The other cells are filled out the same way.
The terms in those four inner cells (gray boxes) are:
The like terms here are -14x and -2x which combine to -16x, since -14+(-2) = -16.
We end up with the answer 4x^2-16x+7
Answer:
Step-by-step explanation:
1. use distribution factor
(4x+3)(24+5x)
4x times 24 = 96
4x times 5x = 20x
3 times 24 = 72
3 times 5x = 15x
2. combine like terms
96 + 72 = 168
15x + 20x = 35x
35x + 168 or 168 + 35x
I may be wrong please check my answer. I may have a lapse in my algebra, or I may have misunderstood the problem. But this is what I can give you to the best of my knowledge.
Answer:
Step-by-step explanation:
The best way to find out the answer to your question is to graph the cubic. As you can see, the y intercept is (0,16).
How was this obtained. notice that if x = 0 then
f(0) = 2(3*0+4)(0^2 + 2)
f(0) = 2(4)(2)
f(0) = 16 just as the graph tells us.
Answer:
The answer to your question is b = 8.06 cm
Step-by-step explanation:
Data
hypotenuse = c = 9 cm
long leg = b = ?
short leg = a = 4 cm
Process
This is a right triangle so we must use the Pythagorean theorem to find the length of the long leg (b)
c² = a² + b²
-Solve for b²
b² = c² - a²
-Substitution
b² = 9² - 4²
-Simplification
b² = 81 - 16
b² = 65
-Result
b = 8.06 cm
Hi there!
It depends on the dimensions of each cords of wood. If each cord of wood is just one square yard large, then you could fit 4*4*2=32 cords of wood into a room that has the dimensions that you described.
-AwesomeRepublic :)
