What is the amount of discount on a $475 TV if the discount is 15%

The diagram shows an empty cylindrical container. Ana puts a solid cube of side length 8 cm into the container. She then pours 1

marshall27 [118]

Answer:

<h3><u>Cylinder</u></h3>

$\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}$

Given:

r = 6 cm

h = 18 cm

$\begin{aligned}\implies \sf V &= \sf \pi (6)^2(18)\\& = \sf 648 \pi \: cm^3\end{aligned}$

$\textsf{Volume of a cube}=\sf x^3\quad\textsf{(where x is the side length)}$

Given:

x = 8 cm

$\begin{aligned}\implies \sf V &= 8^3\\& = \sf 512 \: cm^3\end{aligned}$

<h3><u>Volume available to be filled with water</u></h3>

Volume of cylinder - volume of cube

= 684π - 512

= 1532.75204 cm³

1 litre = 1000 cm³

⇒ 1.5 litres = 1000 × 1.5 = 1500 cm³

As 1500 < 1532.75204, the volume of water poured into the container is smaller than the empty space available in the cylinder. Therefore, the water will <u>not</u> come over the top of the container.

4 0

2 years ago

I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?

Valentin [98]

Given:

In a number, adding $1\dfrac{3}{4}$ , then multiplying the result by $2\dfrac{2}{11}$ we get 8.

To find:

The unknown number.

Solution:

Let the unknown number be x.

According to the question,

$(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8$

$(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8$

$(x+\dfrac{4+3}{4})\times \dfrac{22+2}{11}=8$

$(x+\dfrac{7}{4})\times \dfrac{24}{11}=8$

Multiply both sides by $\dfrac{11}{24}$ .

$x+\dfrac{7}{4}=8\times \dfrac{11}{24}$

$x+\dfrac{7}{4}=\dfrac{11}{3}$

Subtract $\dfrac{7}{4}$ from both sides.

$x=\dfrac{11}{3}-\dfrac{7}{4}$

$x=\dfrac{44-21}{12}$

$x=\dfrac{23}{12}$

$x=1\dfrac{11}{12}$

Therefore, the required number is $1\dfrac{11}{12}$ .

3 0

2 years ago

What’s the domain and range for (2,4) (5,3) (-1,-4) (0,9) (-3,1)

Citrus2011 [14]

Step-by-step explanation: In this problem, we're asked to state the domain and range for the following relation.

First of all, a relation is just a set of ordered pairs like you see in this problem. The domain is the set of all x-coordinates for those ordered pairs. So in this case the domain or D is {2, 5, -1, 0, -3}.

The range is the set of all y-coordinates for those ordered pairs. So in this case our range or R is {4, 3, -4, 9, 1}.

3 0

2 years ago

The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

Delicious77 [7]

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$