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s344n2d4d5 [400]
3 years ago
6

What is the amount of discount on a $475 TV if the discount is 15%

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0
$475*0.15=$71.25 discount
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Lei’s favorite cereal comes in two box sizes. A 16-ounce box costs $3.20. The 32-ounce box costs $6.24. Which box is better to b
Andru [333]

Answer:

The 32-ounce box

Step-by-step explanation:

The 16-ounce box costs $3.20 for every 16 ounces, but the 32-ounce box costs $3.12 for every 16 ounces. That means the 32-ounce box is a better deal by 8 cents.

4 0
3 years ago
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A survey of the 4700 vehicles on the campus of State University yielded the following circle graph. From the survey, how many ca
Vedmedyk [2.9K]

Answer:

198

Step-by-step explanation:

4 0
3 years ago
In the figure, BC is a support for the roof<br> of a garage. What is the length of BC?
Sonbull [250]

Answer:

Bc = √63 ft

Step-by-step explanation:

Here, we want to get the length of BC

As we can see, there is a right angled triangle ABC, with 12ft being the hypotenuse and 9 ft the other side

So we want to get the third leg which is BC

we can use the Pythagoras’ theorem here

And that states that the square of the hypotenuse equals the sum of the squares of the two other sides

let the missing length be x

12^2 = x^2 + 9^2

144 = x^2 + 81

x^2 = 144-81

x^2 = 63

x = √63 ft

4 0
3 years ago
A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
Vinil7 [7]

Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

3 0
1 year ago
What is the distance between the points? Round to the nearest tenth if necessary.
Rom4ik [11]

Answer:

10/4

Step-by-step explanation:

rise over run

8 0
3 years ago
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