(5, 12) e (-10, -3)
x.......y...1
5.....12..1
-10..-3..1
12x -10y -15 + 120 -5y + 3x = 0
12x + 3x - 10y - 5y - 15 + 120 = 0
15x - 15y + 105 = 0 :(5)
3x - 5y + 21 = 0
m = -a/b
m = -3/-5
m(5) = 3/5
y-yo = m(x-xo)
y-14 = 3/5*(x-7)
y-14 = 3x/5 - 7/5
3x/5 - y + 14 - 7/5 = 0
3x/5 - 5y/5 + 70/5 - 7/5 = 0
3x - 5y + 70 - 7 =0
3x - 5y + 63 = 0
m(s) = -3/-5 = 3/5
m(r) = m(s) --> são paralelas
Hi
i just saw your massage just now and you asked for help
so,there is my answer
S=8/100*2000/1
s=160+3840
A=4000
It means approximately equal to.
"<span>The sum of the squares of the digits is 26"
</span>10t + u = 26 ---->(1)
<span>"If the number is decreased by the number with its digits reversed, the result is 36"
u - 10t =36 -----> (2)
By subtracting the equation we can find t.
</span> u+10t = 26)<span>
-(u-10t=36)</span>
______________
0u +20t = 26 -36
---> 20t = -10
t= -10/20
t= -1/2
Inserting value t in (1)
10t + u = 26
10(-1/2) + u= 26
-5+u=26
u= 26+5 = 31
<span>
Using u and t in the original expression 10t+u express a positive number
10t+u
= 10(-1/2) +u
= -5 + 31
= 26
----> Proves this statement is true
</span>"The sum of the squares of the digits is 26"
10t + u = 26 <span>
</span>
Answer:
The solution of the given equations are (3,2).
Step-by-step explanation:
Given equations are :
3d−e=7 ...(1)
d+e=5 ...(2)
Add equations (1) and (2) we get :
3d-e+d+e=7+5
4d = 12
d = 3
Put the value of d in equation (2).
3+e=5
e = 2
So, the value of d = 3 and e = 2. Solution of the given equations are (3,2).
