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zaharov [31]
4 years ago
5

Ten over 18 equals C over 4.5 what does C equal

Mathematics
2 answers:
zaharov [31]4 years ago
8 0
10/18 = c/4.5
4.5 (10) = 18c ...cross multiply
45 = 18c
45/18 = c
2.5 =c
answer: c = 2.5
Jobisdone [24]4 years ago
3 0
10\18=c\4.5 cross multiply
18 x C=10 x 4.5
18 x c=45
c=45-18
c=27

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Find the average value fave of the function f on the given interval. f() = 5 sec2(/6), 0, 3 2
Inessa05 [86]

Answer:

f_{ave} = {\frac{10 }{3\pi }

Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3\pi/2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

f_{ave} = \frac{1}{b - a}\int\limits^b_a {f(x)} \, dx

Now,

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Now,

f_{ave} = \frac{1}{\frac{3\pi }{2}  - 0}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{2 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{10 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ]

      = {\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ]

      = {\frac{10 }{3\pi }}[ {1 - 0 }  ]

      = {\frac{10 }{3\pi }

⇒f_{ave} = {\frac{10 }{3\pi }

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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supplement=

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8 0
3 years ago
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Morgarella [4.7K]
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