The product of two inductive odd integers

Mathematics

1 answer:

vaieri [72.5K]3 years ago

4 0

Let m and n be any integers so that 2m and 2k are two even numbers.

The product is 2m(2k) = 2(2mk), which is even.

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Write the function f(x) = 3x2 - 6x + 5 in vertex

weeeeeb [17]

3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)

7 0

2 years ago

A grocery store purchases bags of chips for $2 and marks up the price by 162%. The store is having a sale where everything is on

drek231 [11]

Answer:

4.62

Step-by-step explanation:

2 * 1.62= 3.24

new cost is $3.24 + 2 = 5.24

5.24 * .12 = .62 discount

5.24 - .62

4.62

7 0

2 years ago

Read 2 more answers

What's the answer to this math problem

GarryVolchara [31]

Total number of marbles:
75 + 50 + 100 + 25 = 250

Probability of selecting a red marble:
25/250 (since 25 out of 250 marbles are red)
Since the top and bottom of this fraction are both divisible by 25, we can go ahead and divide them both by 25, simplifying to 1/10.

Probability of selecting a green marble:
50/250
Simplifies to 2/10
Simplifies to 1/5.

Probability of selecting a blue or orange marble
(75+100)/250
175/250
Simplifies to 7/10.

To find the probability that each event occurs in order, simply multiply them all together.

$\frac{1}{10}\times\frac{1}{5}\times\frac{7}{10}=\frac{1\times1\times7}{10\times5\times10}=\boxed{\frac{7}{500}}$