We will use the following law of indices (or 'index law') to check each pair of expression
![x^{ \frac{m}{n}} = ( \sqrt[n]{x} )^{m}](https://tex.z-dn.net/?f=%20x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%28%20%5Csqrt%5Bn%5D%7Bx%7D%20%29%5E%7Bm%7D%20)
With fractional power, the denominator is the root and the numerator is the power of the term. When the denominator is 2, we usually only write the normal square symbol (√). Denominator other than 2, we usually write the value of the root, for example, the cubic root ∛
Option A - Incorrect

should equal to
Option B - Correct
does equal to

Option C - Incorrect

should equal to

Option D - Incorrect

should equal to
Answer:
Your solution is (-1, 0)
Step-by-step explanation:
3x - y = -3
x + y = -1
The elimination method <em>eliminates</em> one variable at a time to find the other variable.
Here we can see that the y variable will naturally be eliminated.
3x - y = -3
x + y = -1
--------------
4x = -4
Divide both sides by 4 to isolate x.
x = -1
Now plug this value back into one of the equations.
3(-1) - y = -3
Multiply.
-3 - y = -3
Add 3 to both sides.
-y = 0
Divide both sides by -1.
y = 0
Your solution is (-1, 0)
Check this solution by plugging these values into the second equation.
-1 + 0 = -1
-1 = -1
Your solution is correct.
Hope this helps!
Not if you know your mathmatics
Answer:
1.25% widgets from factory A fail.
Step-by-step explanation:
Probability of widgets that fail = 0.05
Probability of failing widget to belong from factory A = 0.25
Probability of failing widget to belong from factory B = 0.35
Probability of failing widget to belong from factory C = 0.40
Probability of factory A widgets failing = Probability of widgets failing * probability they belonged from factory A
Probability of factory A widgets failing = 0.05 * 0.25 = 0.0125
This probability stated as percentage: 1.25%
119,644 is the answer I believe