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3 years ago

Heyyy! can you please help me? : )

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

8 0

Range is is the largest number - the smallest number. So you would do 9-0=9

vampirchik [111]3 years ago

5 0

Answer:

Step-by-step explanation:

The range is the difference between the highest and lowest number.

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3 · 32 + 8 ÷ 2 − (4 + 3)

Lorico [155]

Answer:

93 is your answer.

Step-by-step explanation:

What you want to do is PEMDAS.

3 · 32 + 8 ÷ 2 − (4 + 3)

96 + 8 ÷ 2 - 7

96 + 4 - 7

100 - 7

93 is your answer.

3 0

3 years ago

Read 2 more answers

Solve the simultaneous equations 4x+y = 10 x - 5y = 13

Lina20 [59]

Answer:

1: x-intercept(s): ( $\frac{5}{2}$ ,0)

y-intercept(s): (0,10)

2: x-intercept(s): (13,0)

y-intercept(s): (0,− $\frac{13}{5}$ )

Step-by-step explanation:

8 0

3 years ago

Kevin delivers newspapers in his town every morning. The amount he earns from delivering newspapers is given by y = 30x + 18, wh

Marina CMI [18]

Y=mx+b, b=y-intercept (value of y when x=0) so if:

y=30x+18

He earns 18 cents if he does not make any deliveries.

5 0

3 years ago

Keenan has 28 CDs and 44 DVDs. What is the ratio of DVDs to CDs?

pantera1 [17]

Answer is D.
28:44 is the ratio but you have to simplify it. Divide both by 4. 28 divided by 4 = 7; 44 divided by 4 = 11

4 0

3 years ago

Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1]

Alekssandra [29.7K]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

3 years ago