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3 years ago

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5. A rectangle is 2 1/2meters wide and 3 1/2meters

2 answers:

Helga [31]3 years ago

8 0

Multiply 2 1/2 and 3 1/2, which should get you to 8 3/4 or 8.75 if your using decimals. After multiplying, add the unit (meters) and square it as shown. Hope this helps. :)

Schach [20]3 years ago

6 0

Answer:

The area of the rectangle is 8 3/4 square meters.

Step-by-step explanation:

The area of a rectangle is calculated by multiplying the height by the length.

$2 \frac{1}{2} \times 3 \frac{1}{2} = 2.5 \times 3.5 = 8.75$

The area of an object is defined in square meters (m2) rather than regular meters.

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3 years ago

The sum of three numbers is 45. One number is five more than a second number. It is also twice the third. Find the numbers.

blagie [28]

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3 years ago

Read 2 more answers

A school buys a box of staples to refill all 28 staplers in the building. The box has 5,000 total Staples and there are 210 Stap

Rom4ik [11]

a) if you have 5000 staples can you fill 28 staplers with 210 staples in each stapler? and you need to find out if there are enough staples to fill all 28 staplers

b) multiplication and division

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8 0

3 years ago

Rewrite the logarithm as an exponential equation: <br> In(X)= 7

Leto [7]

Answer:

$e^7=x$

Step-by-step explanation:

Given the logarithm function

$In\left(x\right)=\:7$

For logarithmic equations, $\log _b\left(x\right)=y$ is equivalent to $b^y=x$ such that

$x>0\:,\:b>0$ and $b\ne 1$

In current case:

$b=e\:$

$\:x=x$

$\:y=7$

Substituting the values of $b\:,\:x\:$ and $y$ into the equation $b^y=x$

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4 0

4 years ago

A manufacturer makes chocolate squares that have a target weight of 8 g. Quality control engineers sample 30 chocolate squares t

posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is $\mu = 8.5$ .

The standard deviation is $\sigma = 0.87$ .

A sample of 30 is taken, hence $n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588$ .

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{8 - 8.5}{0.1588}$

$Z = -3.15$

$Z = -3.15$ has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

5 0

3 years ago