Answer:
Step-by-step explanation:
The heights of neither the rectangular prism nor the triangular prism are given, so we don't know the volume of either.
If h is the height of the rectangular prism, then its volume is
6×8×h = 48
if the height of the triangular prism is h/2, then its volume is
(1/2)×24×8×(h/2) = 48
So we know the volumes are the same -- but we don't know what that volume is.
This problem can be represented through the following equation
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
For a 30 sided regular polygon, We can divide the polygon (30 sides) into 30 inscribed triangles with central vertex angles of =
.
This central vertex angle of <u>12 degrees</u> is the degree of rotation for a 30 sided polygon.
In other words, the 30 sided polygon has <u>12 degree</u> rotational symmetry about the center.
9514 1404 393
Answer:
6.2
Step-by-step explanation:
We presume your "k-value" is the k in the exponential decay term ...
e^(-kt) . . . where t is the number of time units
This is 1/2 when ...
ln(1/2) = -kt
t = ln(1/2)/(-k) = ln(2)/k
t = 0.69315/0.1124 ≈ 6.2
The half life is about 6.2 time units.