Answer:
1=43
2=61
3=79
4=97
5=115
Step-by-step explanation:
25+18=43
43+18=61
and so on
Answer:
140 drops
Step-by-step explanation:
Length of the pool = 24 feet
Width of the pool = 14 feet
Depth of the pool = 5 feet
Volume of the pool = length × width × depth
= 24 ft * 14 ft * 5 ft
= 1,750 ft³
Volume of the pool = 1,750 ft³
He needs to add 4 drops of chlorine for every 50 cubic feet in his pool.
Number of 50 cubic feet in the volume of the pool = Volume of the pool / 50 ft³
= 1,750 ft³ / 50 ft³
= 35
Number of 50 cubic feet in the volume of the pool = 35
How many drops of chlorine should Jorge use to chlorinate his pool properly?
Number of drops of chlorine Jorge should use = number of drops per 50 ft³ × Number of 50 cubic feet in the volume of the pool
= 4 × 35
= 140 drops
Number of drops of chlorine Jorge should use = 140 drops
Statement Reason
<span>∆ABC and ∆ADC are isosceles Given
Segment AC is a common base
to </span><span>∆ABC and ∆ADC Given
Let K be the midpoint of the base
of </span><span>segment AC, then BK is the
perpendicular bisector of segment </span><span>perpendicular bisector of isosceles AC. triangle property.</span>
Also, <span>DK is the perpendicular
bisector of segment AC. </span><span>perpendicular bisector of isosceles triangle property.</span>
Answer:
257169554605/657 or about 391430068