You have the numbers 1-24 written on slips of paper. If you choose one slip at random, what is the probability that you will not

Question

Oxana [17]

3 years ago

15

You have the numbers 1-24 written on slips of paper. If you choose one slip at random, what is the probability that you will not

select a number which is divisible by 3?

Mathematics

1 answer:

ra1l [238] · Answer 1 · 2022-03-13T13:27:19+03:00

The probability of selecting a number not divisible by 3 is: 2/3

Step-by-step explanation:

There are two methods to solve the question.

We can find the probability of numbers not divisible by 3
We can find the probability of numbers divisible by 3 and then find the complement of it

We will use the second method:

Given:

There are 24 slips

S = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}

n(S) = 24

Let A be the event that the slip number is divisible by 3

Then

A = {3,6,9,12,15,18,21,24}

n(A) = 8

The probability of number divisible by 3 is:

$P(A) = \frac{n(A)}{n(S)}\\=\frac{8}{24}\\=\frac{1}{3}$

The sum of the probability of an event's occurrence and non-occurrence is 1. So the probability of numbers divisible by 3 will be subtracted from 1 to find the probability of selecting a number not divisible by 3.

The probability of selecting a number not divisible by 3 will be:

$=1-\frac{1}{3}\\=\frac{3-1}{3}\\=\frac{2}{3}$

The probability of selecting a number not divisible by 3 is: 2/3

Keywords: Probability

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